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Hitungan: Untuk f (t) = (sqrt (t) / (t + 1), t ^ 2-t) berapa jarak antara f (0) dan f (2)? - 2020

Anonim

Menjawab:

# 2 / 3sqrt (10) #

Penjelasan:

Jika #f (t) = (sqrt (t) / (t + 1), t ^ 2-t) #
kemudian
#color (white) ("XXX") f (0) = (sqrt (0) / (0 + 1), 0 ^ 2-0) = (0,0) #

#color (white) ("XXX") f (2) = (sqrt (2) / (2 + 1), 2 ^ 2-2) = (sqrt (2) / 3,2) #

Jarak antara #f (0) # dan #f (2) # dapat dihitung menggunakan Teorema Pythagoras
#color (white) ("XXX") d = sqrt ((sqrt (2) / 3-0) ^ 2 + (2-0) ^ 2) #

#color (white) ("XXX") = sqrt (4/9 + 4) #

#color (white) ("XXX") = sqrt (40/9) #

#color (white) ("XXX") = 2 / 3sqrt (10) #